In the figure, EFG is parallel to KLM and the line KG cuts ∠FKM into half. Given that GK and FL are straight lines, ∠EFK = 43°, ∠KLJ = 42° and ∠FJG = 117°, find
- ∠b
- ∠d
- ∠c
(a)
∠KJL = ∠FJG = 117° (Vertically opposite angles)
∠b
= 180° - 117° - 42°
= 21° (Angles sum of triangle)
(b)
∠d
= 180° - 21°
= 159° (Interior angles)
(c)
∠c
= 180° - 21° - 21° - 42°
= 95° (Angles sum of triangle)
Answer(s): (a) 21°; (b) 159°; (c) 95°