In the figure, MNP is parallel to STU and the line SP cuts ∠NSU into half. Given that PS and NT are straight lines, ∠MNS = 45°, ∠STR = 34° and ∠NRP = 117°, find
- ∠b
- ∠d
- ∠c
(a)
∠SRT = ∠NRP = 117° (Vertically opposite angles)
∠b
= 180° - 117° - 34°
= 29° (Angles sum of triangle)
(b)
∠d
= 180° - 29°
= 151° (Interior angles)
(c)
∠c
= 180° - 29° - 29° - 34°
= 101° (Angles sum of triangle)
Answer(s): (a) 29°; (b) 151°; (c) 101°