In the figure, MNP is parallel to STU and the line SP cuts ∠NSU into half. Given that PS and NT are straight lines, ∠MNS = 41°, ∠STR = 34° and ∠NRP = 111°, find
- ∠g
- ∠i
- ∠h
(a)
∠SRT = ∠NRP = 111° (Vertically opposite angles)
∠g
= 180° - 111° - 34°
= 35° (Angles sum of triangle)
(b)
∠i
= 180° - 35°
= 145° (Interior angles)
(c)
∠h
= 180° - 35° - 35° - 34°
= 105° (Angles sum of triangle)
Answer(s): (a) 35°; (b) 145°; (c) 105°