In the figure, QRS is parallel to VWX and the line VS cuts ∠RVX into half. Given that SV and RW are straight lines, ∠QRV = 44°, ∠VWU = 33° and ∠RUS = 120°, find
- ∠n
- ∠q
- ∠p
(a)
∠VUW = ∠RUS = 120° (Vertically opposite angles)
∠n
= 180° - 120° - 33°
= 27° (Angles sum of triangle)
(b)
∠q
= 180° - 27°
= 153° (Interior angles)
(c)
∠p
= 180° - 27° - 27° - 33°
= 103° (Angles sum of triangle)
Answer(s): (a) 27°; (b) 153°; (c) 103°