In the figure, RST is parallel to WXY and the line WT cuts ∠SWY into half. Given that TW and SX are straight lines, ∠RSW = 42°, ∠WXV = 36° and ∠SVT = 116°, find
- ∠s
- ∠v
- ∠t
(a)
∠WVX = ∠SVT = 116° (Vertically opposite angles)
∠s
= 180° - 116° - 36°
= 28° (Angles sum of triangle)
(b)
∠v
= 180° - 28°
= 152° (Interior angles)
(c)
∠t
= 180° - 28° - 28° - 36°
= 102° (Angles sum of triangle)
Answer(s): (a) 28°; (b) 152°; (c) 102°