In the figure, EFG is parallel to KLM and the line KG cuts ∠FKM into half. Given that GK and FL are straight lines, ∠EFK = 49°, ∠KLJ = 37° and ∠FJG = 119°, find
- ∠e
- ∠g
- ∠f
(a)
∠KJL = ∠FJG = 119° (Vertically opposite angles)
∠e
= 180° - 119° - 37°
= 24° (Angles sum of triangle)
(b)
∠g
= 180° - 24°
= 156° (Interior angles)
(c)
∠f
= 180° - 24° - 24° - 37°
= 94° (Angles sum of triangle)
Answer(s): (a) 24°; (b) 156°; (c) 94°