In the figure, RST is parallel to WXY and the line WT cuts ∠SWY into half. Given that TW and SX are straight lines, ∠RSW = 44°, ∠WXV = 41° and ∠SVT = 120°, find
- ∠r
- ∠t
- ∠s
(a)
∠WVX = ∠SVT = 120° (Vertically opposite angles)
∠r
= 180° - 120° - 41°
= 19° (Angles sum of triangle)
(b)
∠t
= 180° - 19°
= 161° (Interior angles)
(c)
∠s
= 180° - 19° - 19° - 41°
= 95° (Angles sum of triangle)
Answer(s): (a) 19°; (b) 161°; (c) 95°