In the figure, NPQ is parallel to TUV and the line TQ cuts ∠PTV into half. Given that QT and PU are straight lines, ∠NPT = 45°, ∠TUS = 36° and ∠PSQ = 119°, find
- ∠h
- ∠j
- ∠i
(a)
∠TSU = ∠PSQ = 119° (Vertically opposite angles)
∠h
= 180° - 119° - 36°
= 25° (Angles sum of triangle)
(b)
∠j
= 180° - 25°
= 155° (Interior angles)
(c)
∠i
= 180° - 25° - 25° - 36°
= 99° (Angles sum of triangle)
Answer(s): (a) 25°; (b) 155°; (c) 99°