In the figure, DEF is parallel to JKL and the line JF cuts ∠EJL into half. Given that FJ and EK are straight lines, ∠DEJ = 44°, ∠JKH = 32° and ∠EHF = 115°, find
- ∠r
- ∠t
- ∠s
(a)
∠JHK = ∠EHF = 115° (Vertically opposite angles)
∠r
= 180° - 115° - 32°
= 33° (Angles sum of triangle)
(b)
∠t
= 180° - 33°
= 147° (Interior angles)
(c)
∠s
= 180° - 33° - 33° - 32°
= 104° (Angles sum of triangle)
Answer(s): (a) 33°; (b) 147°; (c) 104°