In the figure, CDE is parallel to HJK and the line HE cuts ∠DHK into half. Given that EH and DJ are straight lines, ∠CDH = 46°, ∠HJG = 34° and ∠DGE = 115°, find
- ∠c
- ∠e
- ∠d
(a)
∠HGJ = ∠DGE = 115° (Vertically opposite angles)
∠c
= 180° - 115° - 34°
= 31° (Angles sum of triangle)
(b)
∠e
= 180° - 31°
= 149° (Interior angles)
(c)
∠d
= 180° - 31° - 31° - 34°
= 100° (Angles sum of triangle)
Answer(s): (a) 31°; (b) 149°; (c) 100°