In the figure, RST is parallel to WXY and the line WT cuts ∠SWY into half. Given that TW and SX are straight lines, ∠RSW = 42°, ∠WXV = 41° and ∠SVT = 117°, find
- ∠a
- ∠c
- ∠b
(a)
∠WVX = ∠SVT = 117° (Vertically opposite angles)
∠a
= 180° - 117° - 41°
= 22° (Angles sum of triangle)
(b)
∠c
= 180° - 22°
= 158° (Interior angles)
(c)
∠b
= 180° - 22° - 22° - 41°
= 97° (Angles sum of triangle)
Answer(s): (a) 22°; (b) 158°; (c) 97°