In the figure, FGH is parallel to LMN and the line LH cuts ∠GLN into half. Given that HL and GM are straight lines, ∠FGL = 43°, ∠LMK = 35° and ∠GKH = 113°, find
- ∠f
- ∠h
- ∠g
(a)
∠LKM = ∠GKH = 113° (Vertically opposite angles)
∠f
= 180° - 113° - 35°
= 32° (Angles sum of triangle)
(b)
∠h
= 180° - 32°
= 148° (Interior angles)
(c)
∠g
= 180° - 32° - 32° - 35°
= 102° (Angles sum of triangle)
Answer(s): (a) 32°; (b) 148°; (c) 102°