In the figure, FGH is parallel to LMN and the line LH cuts ∠GLN into half. Given that HL and GM are straight lines, ∠FGL = 42°, ∠LMK = 37° and ∠GKH = 117°, find
- ∠w
- ∠y
- ∠x
(a)
∠LKM = ∠GKH = 117° (Vertically opposite angles)
∠w
= 180° - 117° - 37°
= 26° (Angles sum of triangle)
(b)
∠y
= 180° - 26°
= 154° (Interior angles)
(c)
∠x
= 180° - 26° - 26° - 37°
= 101° (Angles sum of triangle)
Answer(s): (a) 26°; (b) 154°; (c) 101°