In the figure, RST is parallel to WXY and the line WT cuts ∠SWY into half. Given that TW and SX are straight lines, ∠RSW = 50°, ∠WXV = 39° and ∠SVT = 110°, find
- ∠r
- ∠t
- ∠s
(a)
∠WVX = ∠SVT = 110° (Vertically opposite angles)
∠r
= 180° - 110° - 39°
= 31° (Angles sum of triangle)
(b)
∠t
= 180° - 31°
= 149° (Interior angles)
(c)
∠s
= 180° - 31° - 31° - 39°
= 91° (Angles sum of triangle)
Answer(s): (a) 31°; (b) 149°; (c) 91°