In the figure, QRS is parallel to VWX and the line VS cuts ∠RVX into half. Given that SV and RW are straight lines, ∠QRV = 41°, ∠VWU = 39° and ∠RUS = 113°, find
- ∠n
- ∠q
- ∠p
(a)
∠VUW = ∠RUS = 113° (Vertically opposite angles)
∠n
= 180° - 113° - 39°
= 28° (Angles sum of triangle)
(b)
∠q
= 180° - 28°
= 152° (Interior angles)
(c)
∠p
= 180° - 28° - 28° - 39°
= 100° (Angles sum of triangle)
Answer(s): (a) 28°; (b) 152°; (c) 100°