In the figure, BCD is parallel to GHJ and the line GD cuts ∠CGJ into half. Given that DG and CH are straight lines, ∠BCG = 48°, ∠GHF = 40° and ∠CFD = 119°, find
- ∠s
- ∠v
- ∠t
(a)
∠GFH = ∠CFD = 119° (Vertically opposite angles)
∠s
= 180° - 119° - 40°
= 21° (Angles sum of triangle)
(b)
∠v
= 180° - 21°
= 159° (Interior angles)
(c)
∠t
= 180° - 21° - 21° - 40°
= 92° (Angles sum of triangle)
Answer(s): (a) 21°; (b) 159°; (c) 92°