In the figure, JKL is parallel to PQR and the line PL cuts ∠KPR into half. Given that LP and KQ are straight lines, ∠JKP = 44°, ∠PQN = 36° and ∠KNL = 113°, find
- ∠p
- ∠r
- ∠q
(a)
∠PNQ = ∠KNL = 113° (Vertically opposite angles)
∠p
= 180° - 113° - 36°
= 31° (Angles sum of triangle)
(b)
∠r
= 180° - 31°
= 149° (Interior angles)
(c)
∠q
= 180° - 31° - 31° - 36°
= 100° (Angles sum of triangle)
Answer(s): (a) 31°; (b) 149°; (c) 100°