In the figure, JKL is parallel to PQR and the line PL cuts ∠KPR into half. Given that LP and KQ are straight lines, ∠JKP = 43°, ∠PQN = 38° and ∠KNL = 113°, find
- ∠s
- ∠v
- ∠t
(a)
∠PNQ = ∠KNL = 113° (Vertically opposite angles)
∠s
= 180° - 113° - 38°
= 29° (Angles sum of triangle)
(b)
∠v
= 180° - 29°
= 151° (Interior angles)
(c)
∠t
= 180° - 29° - 29° - 38°
= 99° (Angles sum of triangle)
Answer(s): (a) 29°; (b) 151°; (c) 99°