In the figure, BCD is parallel to GHJ and the line GD cuts ∠CGJ into half. Given that DG and CH are straight lines, ∠BCG = 50°, ∠GHF = 33° and ∠CFD = 110°, find
- ∠g
- ∠i
- ∠h
(a)
∠GFH = ∠CFD = 110° (Vertically opposite angles)
∠g
= 180° - 110° - 33°
= 37° (Angles sum of triangle)
(b)
∠i
= 180° - 37°
= 143° (Interior angles)
(c)
∠h
= 180° - 37° - 37° - 33°
= 97° (Angles sum of triangle)
Answer(s): (a) 37°; (b) 143°; (c) 97°