In the figure, CDE is parallel to HJK and the line HE cuts ∠DHK into half. Given that EH and DJ are straight lines, ∠CDH = 49°, ∠HJG = 37° and ∠DGE = 115°, find
- ∠x
- ∠z
- ∠y
(a)
∠HGJ = ∠DGE = 115° (Vertically opposite angles)
∠x
= 180° - 115° - 37°
= 28° (Angles sum of triangle)
(b)
∠z
= 180° - 28°
= 152° (Interior angles)
(c)
∠y
= 180° - 28° - 28° - 37°
= 94° (Angles sum of triangle)
Answer(s): (a) 28°; (b) 152°; (c) 94°