In the figure, CDE is parallel to HJK and the line HE cuts ∠DHK into half. Given that EH and DJ are straight lines, ∠CDH = 50°, ∠HJG = 41° and ∠DGE = 110°, find
- ∠d
- ∠f
- ∠e
(a)
∠HGJ = ∠DGE = 110° (Vertically opposite angles)
∠d
= 180° - 110° - 41°
= 29° (Angles sum of triangle)
(b)
∠f
= 180° - 29°
= 151° (Interior angles)
(c)
∠e
= 180° - 29° - 29° - 41°
= 89° (Angles sum of triangle)
Answer(s): (a) 29°; (b) 151°; (c) 89°