In the figure, HJK is parallel to NPQ and the line NK cuts ∠JNQ into half. Given that KN and JP are straight lines, ∠HJN = 42°, ∠NPM = 36° and ∠JMK = 120°, find
- ∠h
- ∠j
- ∠i
(a)
∠NMP = ∠JMK = 120° (Vertically opposite angles)
∠h
= 180° - 120° - 36°
= 24° (Angles sum of triangle)
(b)
∠j
= 180° - 24°
= 156° (Interior angles)
(c)
∠i
= 180° - 24° - 24° - 36°
= 102° (Angles sum of triangle)
Answer(s): (a) 24°; (b) 156°; (c) 102°