In the figure, BCD is parallel to GHJ and the line GD cuts ∠CGJ into half. Given that DG and CH are straight lines, ∠BCG = 41°, ∠GHF = 39° and ∠CFD = 114°, find
- ∠b
- ∠d
- ∠c
(a)
∠GFH = ∠CFD = 114° (Vertically opposite angles)
∠b
= 180° - 114° - 39°
= 27° (Angles sum of triangle)
(b)
∠d
= 180° - 27°
= 153° (Interior angles)
(c)
∠c
= 180° - 27° - 27° - 39°
= 100° (Angles sum of triangle)
Answer(s): (a) 27°; (b) 153°; (c) 100°