In the figure, MNP is parallel to STU and the line SP cuts ∠NSU into half. Given that PS and NT are straight lines, ∠MNS = 48°, ∠STR = 33° and ∠NRP = 117°, find
- ∠x
- ∠z
- ∠y
(a)
∠SRT = ∠NRP = 117° (Vertically opposite angles)
∠x
= 180° - 117° - 33°
= 30° (Angles sum of triangle)
(b)
∠z
= 180° - 30°
= 150° (Interior angles)
(c)
∠y
= 180° - 30° - 30° - 33°
= 99° (Angles sum of triangle)
Answer(s): (a) 30°; (b) 150°; (c) 99°