In the figure, RST is parallel to WXY and the line WT cuts ∠SWY into half. Given that TW and SX are straight lines, ∠RSW = 41°, ∠WXV = 36° and ∠SVT = 110°, find
- ∠x
- ∠z
- ∠y
(a)
∠WVX = ∠SVT = 110° (Vertically opposite angles)
∠x
= 180° - 110° - 36°
= 34° (Angles sum of triangle)
(b)
∠z
= 180° - 34°
= 146° (Interior angles)
(c)
∠y
= 180° - 34° - 34° - 36°
= 103° (Angles sum of triangle)
Answer(s): (a) 34°; (b) 146°; (c) 103°