In the figure, FGH is parallel to LMN and the line LH cuts ∠GLN into half. Given that HL and GM are straight lines, ∠FGL = 42°, ∠LMK = 40° and ∠GKH = 118°, find
- ∠m
- ∠p
- ∠n
(a)
∠LKM = ∠GKH = 118° (Vertically opposite angles)
∠m
= 180° - 118° - 40°
= 22° (Angles sum of triangle)
(b)
∠p
= 180° - 22°
= 158° (Interior angles)
(c)
∠n
= 180° - 22° - 22° - 40°
= 98° (Angles sum of triangle)
Answer(s): (a) 22°; (b) 158°; (c) 98°