In the figure, CDE is parallel to HJK and the line HE cuts ∠DHK into half. Given that EH and DJ are straight lines, ∠CDH = 50°, ∠HJG = 39° and ∠DGE = 112°, find
- ∠w
- ∠y
- ∠x
(a)
∠HGJ = ∠DGE = 112° (Vertically opposite angles)
∠w
= 180° - 112° - 39°
= 29° (Angles sum of triangle)
(b)
∠y
= 180° - 29°
= 151° (Interior angles)
(c)
∠x
= 180° - 29° - 29° - 39°
= 91° (Angles sum of triangle)
Answer(s): (a) 29°; (b) 151°; (c) 91°