In the figure, HJK is parallel to NPQ and the line NK cuts ∠JNQ into half. Given that KN and JP are straight lines, ∠HJN = 41°, ∠NPM = 34° and ∠JMK = 112°, find
- ∠b
- ∠d
- ∠c
(a)
∠NMP = ∠JMK = 112° (Vertically opposite angles)
∠b
= 180° - 112° - 34°
= 34° (Angles sum of triangle)
(b)
∠d
= 180° - 34°
= 146° (Interior angles)
(c)
∠c
= 180° - 34° - 34° - 34°
= 105° (Angles sum of triangle)
Answer(s): (a) 34°; (b) 146°; (c) 105°