In the figure, RST is parallel to WXY and the line WT cuts ∠SWY into half. Given that TW and SX are straight lines, ∠RSW = 48°, ∠WXV = 33° and ∠SVT = 112°, find
- ∠i
- ∠k
- ∠j
(a)
∠WVX = ∠SVT = 112° (Vertically opposite angles)
∠i
= 180° - 112° - 33°
= 35° (Angles sum of triangle)
(b)
∠k
= 180° - 35°
= 145° (Interior angles)
(c)
∠j
= 180° - 35° - 35° - 33°
= 99° (Angles sum of triangle)
Answer(s): (a) 35°; (b) 145°; (c) 99°