In the figure, RST is parallel to WXY and the line WT cuts ∠SWY into half. Given that TW and SX are straight lines, ∠RSW = 45°, ∠WXV = 33° and ∠SVT = 110°, find
- ∠h
- ∠j
- ∠i
(a)
∠WVX = ∠SVT = 110° (Vertically opposite angles)
∠h
= 180° - 110° - 33°
= 37° (Angles sum of triangle)
(b)
∠j
= 180° - 37°
= 143° (Interior angles)
(c)
∠i
= 180° - 37° - 37° - 33°
= 102° (Angles sum of triangle)
Answer(s): (a) 37°; (b) 143°; (c) 102°