In the figure, MNP is parallel to STU and the line SP cuts ∠NSU into half. Given that PS and NT are straight lines, ∠MNS = 49°, ∠STR = 32° and ∠NRP = 118°, find
- ∠r
- ∠t
- ∠s
(a)
∠SRT = ∠NRP = 118° (Vertically opposite angles)
∠r
= 180° - 118° - 32°
= 30° (Angles sum of triangle)
(b)
∠t
= 180° - 30°
= 150° (Interior angles)
(c)
∠s
= 180° - 30° - 30° - 32°
= 99° (Angles sum of triangle)
Answer(s): (a) 30°; (b) 150°; (c) 99°