In the figure, EFG is parallel to KLM and the line KG cuts ∠FKM into half. Given that GK and FL are straight lines, ∠EFK = 50°, ∠KLJ = 39° and ∠FJG = 117°, find
- ∠i
- ∠k
- ∠j
(a)
∠KJL = ∠FJG = 117° (Vertically opposite angles)
∠i
= 180° - 117° - 39°
= 24° (Angles sum of triangle)
(b)
∠k
= 180° - 24°
= 156° (Interior angles)
(c)
∠j
= 180° - 24° - 24° - 39°
= 91° (Angles sum of triangle)
Answer(s): (a) 24°; (b) 156°; (c) 91°