In the figure, DEF is parallel to JKL and the line JF cuts ∠EJL into half. Given that FJ and EK are straight lines, ∠DEJ = 49°, ∠JKH = 39° and ∠EHF = 112°, find
- ∠s
- ∠v
- ∠t
(a)
∠JHK = ∠EHF = 112° (Vertically opposite angles)
∠s
= 180° - 112° - 39°
= 29° (Angles sum of triangle)
(b)
∠v
= 180° - 29°
= 151° (Interior angles)
(c)
∠t
= 180° - 29° - 29° - 39°
= 92° (Angles sum of triangle)
Answer(s): (a) 29°; (b) 151°; (c) 92°