In the figure, CDE is parallel to HJK and the line HE cuts ∠DHK into half. Given that EH and DJ are straight lines, ∠CDH = 49°, ∠HJG = 35° and ∠DGE = 120°, find
- ∠e
- ∠g
- ∠f
(a)
∠HGJ = ∠DGE = 120° (Vertically opposite angles)
∠e
= 180° - 120° - 35°
= 25° (Angles sum of triangle)
(b)
∠g
= 180° - 25°
= 155° (Interior angles)
(c)
∠f
= 180° - 25° - 25° - 35°
= 96° (Angles sum of triangle)
Answer(s): (a) 25°; (b) 155°; (c) 96°