In the figure, CDE is parallel to HJK and the line HE cuts ∠DHK into half. Given that EH and DJ are straight lines, ∠CDH = 43°, ∠HJG = 36° and ∠DGE = 110°, find
- ∠t
- ∠w
- ∠v
(a)
∠HGJ = ∠DGE = 110° (Vertically opposite angles)
∠t
= 180° - 110° - 36°
= 34° (Angles sum of triangle)
(b)
∠w
= 180° - 34°
= 146° (Interior angles)
(c)
∠v
= 180° - 34° - 34° - 36°
= 101° (Angles sum of triangle)
Answer(s): (a) 34°; (b) 146°; (c) 101°