In the figure, DEF is parallel to JKL and the line JF cuts ∠EJL into half. Given that FJ and EK are straight lines, ∠DEJ = 48°, ∠JKH = 32° and ∠EHF = 116°, find
- ∠w
- ∠y
- ∠x
(a)
∠JHK = ∠EHF = 116° (Vertically opposite angles)
∠w
= 180° - 116° - 32°
= 32° (Angles sum of triangle)
(b)
∠y
= 180° - 32°
= 148° (Interior angles)
(c)
∠x
= 180° - 32° - 32° - 32°
= 100° (Angles sum of triangle)
Answer(s): (a) 32°; (b) 148°; (c) 100°