In the figure, HJK is parallel to NPQ and the line NK cuts ∠JNQ into half. Given that KN and JP are straight lines, ∠HJN = 49°, ∠NPM = 36° and ∠JMK = 113°, find
- ∠g
- ∠i
- ∠h
(a)
∠NMP = ∠JMK = 113° (Vertically opposite angles)
∠g
= 180° - 113° - 36°
= 31° (Angles sum of triangle)
(b)
∠i
= 180° - 31°
= 149° (Interior angles)
(c)
∠h
= 180° - 31° - 31° - 36°
= 95° (Angles sum of triangle)
Answer(s): (a) 31°; (b) 149°; (c) 95°