In the figure, QRS is parallel to VWX and the line VS cuts ∠RVX into half. Given that SV and RW are straight lines, ∠QRV = 43°, ∠VWU = 41° and ∠RUS = 117°, find
- ∠w
- ∠y
- ∠x
(a)
∠VUW = ∠RUS = 117° (Vertically opposite angles)
∠w
= 180° - 117° - 41°
= 22° (Angles sum of triangle)
(b)
∠y
= 180° - 22°
= 158° (Interior angles)
(c)
∠x
= 180° - 22° - 22° - 41°
= 96° (Angles sum of triangle)
Answer(s): (a) 22°; (b) 158°; (c) 96°