In the figure, CDE is parallel to HJK and the line HE cuts ∠DHK into half. Given that EH and DJ are straight lines, ∠CDH = 41°, ∠HJG = 35° and ∠DGE = 118°, find
- ∠m
- ∠p
- ∠n
(a)
∠HGJ = ∠DGE = 118° (Vertically opposite angles)
∠m
= 180° - 118° - 35°
= 27° (Angles sum of triangle)
(b)
∠p
= 180° - 27°
= 153° (Interior angles)
(c)
∠n
= 180° - 27° - 27° - 35°
= 104° (Angles sum of triangle)
Answer(s): (a) 27°; (b) 153°; (c) 104°