In the figure, EFG is parallel to KLM and the line KG cuts ∠FKM into half. Given that GK and FL are straight lines, ∠EFK = 42°, ∠KLJ = 37° and ∠FJG = 115°, find
- ∠r
- ∠t
- ∠s
(a)
∠KJL = ∠FJG = 115° (Vertically opposite angles)
∠r
= 180° - 115° - 37°
= 28° (Angles sum of triangle)
(b)
∠t
= 180° - 28°
= 152° (Interior angles)
(c)
∠s
= 180° - 28° - 28° - 37°
= 101° (Angles sum of triangle)
Answer(s): (a) 28°; (b) 152°; (c) 101°