In the figure, FGH is parallel to LMN and the line LH cuts ∠GLN into half. Given that HL and GM are straight lines, ∠FGL = 41°, ∠LMK = 34° and ∠GKH = 110°, find
- ∠t
- ∠w
- ∠v
(a)
∠LKM = ∠GKH = 110° (Vertically opposite angles)
∠t
= 180° - 110° - 34°
= 36° (Angles sum of triangle)
(b)
∠w
= 180° - 36°
= 144° (Interior angles)
(c)
∠v
= 180° - 36° - 36° - 34°
= 105° (Angles sum of triangle)
Answer(s): (a) 36°; (b) 144°; (c) 105°