In the figure, EFG is parallel to KLM and the line KG cuts ∠FKM into half. Given that GK and FL are straight lines, ∠EFK = 44°, ∠KLJ = 32° and ∠FJG = 113°, find
- ∠m
- ∠p
- ∠n
(a)
∠KJL = ∠FJG = 113° (Vertically opposite angles)
∠m
= 180° - 113° - 32°
= 35° (Angles sum of triangle)
(b)
∠p
= 180° - 35°
= 145° (Interior angles)
(c)
∠n
= 180° - 35° - 35° - 32°
= 104° (Angles sum of triangle)
Answer(s): (a) 35°; (b) 145°; (c) 104°