In the figure, NPQ is parallel to TUV and the line TQ cuts ∠PTV into half. Given that QT and PU are straight lines, ∠NPT = 50°, ∠TUS = 38° and ∠PSQ = 119°, find
- ∠a
- ∠c
- ∠b
(a)
∠TSU = ∠PSQ = 119° (Vertically opposite angles)
∠a
= 180° - 119° - 38°
= 23° (Angles sum of triangle)
(b)
∠c
= 180° - 23°
= 157° (Interior angles)
(c)
∠b
= 180° - 23° - 23° - 38°
= 92° (Angles sum of triangle)
Answer(s): (a) 23°; (b) 157°; (c) 92°