In the figure, DEF is parallel to JKL and the line JF cuts ∠EJL into half. Given that FJ and EK are straight lines, ∠DEJ = 43°, ∠JKH = 35° and ∠EHF = 114°, find
- ∠a
- ∠c
- ∠b
(a)
∠JHK = ∠EHF = 114° (Vertically opposite angles)
∠a
= 180° - 114° - 35°
= 31° (Angles sum of triangle)
(b)
∠c
= 180° - 31°
= 149° (Interior angles)
(c)
∠b
= 180° - 31° - 31° - 35°
= 102° (Angles sum of triangle)
Answer(s): (a) 31°; (b) 149°; (c) 102°