In the figure, MNP is parallel to STU and the line SP cuts ∠NSU into half. Given that PS and NT are straight lines, ∠MNS = 42°, ∠STR = 38° and ∠NRP = 119°, find
- ∠j
- ∠m
- ∠k
(a)
∠SRT = ∠NRP = 119° (Vertically opposite angles)
∠j
= 180° - 119° - 38°
= 23° (Angles sum of triangle)
(b)
∠m
= 180° - 23°
= 157° (Interior angles)
(c)
∠k
= 180° - 23° - 23° - 38°
= 100° (Angles sum of triangle)
Answer(s): (a) 23°; (b) 157°; (c) 100°