In the figure, CDE is parallel to HJK and the line HE cuts ∠DHK into half. Given that EH and DJ are straight lines, ∠CDH = 42°, ∠HJG = 33° and ∠DGE = 118°, find
- ∠b
- ∠d
- ∠c
(a)
∠HGJ = ∠DGE = 118° (Vertically opposite angles)
∠b
= 180° - 118° - 33°
= 29° (Angles sum of triangle)
(b)
∠d
= 180° - 29°
= 151° (Interior angles)
(c)
∠c
= 180° - 29° - 29° - 33°
= 105° (Angles sum of triangle)
Answer(s): (a) 29°; (b) 151°; (c) 105°