In the figure, JKL is parallel to PQR and the line PL cuts ∠KPR into half. Given that LP and KQ are straight lines, ∠JKP = 50°, ∠PQN = 41° and ∠KNL = 116°, find
- ∠w
- ∠y
- ∠x
(a)
∠PNQ = ∠KNL = 116° (Vertically opposite angles)
∠w
= 180° - 116° - 41°
= 23° (Angles sum of triangle)
(b)
∠y
= 180° - 23°
= 157° (Interior angles)
(c)
∠x
= 180° - 23° - 23° - 41°
= 89° (Angles sum of triangle)
Answer(s): (a) 23°; (b) 157°; (c) 89°