In the figure, NPQ is parallel to TUV and the line TQ cuts ∠PTV into half. Given that QT and PU are straight lines, ∠NPT = 49°, ∠TUS = 40° and ∠PSQ = 120°, find
- ∠f
- ∠h
- ∠g
(a)
∠TSU = ∠PSQ = 120° (Vertically opposite angles)
∠f
= 180° - 120° - 40°
= 20° (Angles sum of triangle)
(b)
∠h
= 180° - 20°
= 160° (Interior angles)
(c)
∠g
= 180° - 20° - 20° - 40°
= 91° (Angles sum of triangle)
Answer(s): (a) 20°; (b) 160°; (c) 91°