In the figure, BCD is parallel to GHJ and the line GD cuts ∠CGJ into half. Given that DG and CH are straight lines, ∠BCG = 46°, ∠GHF = 37° and ∠CFD = 113°, find
- ∠i
- ∠k
- ∠j
(a)
∠GFH = ∠CFD = 113° (Vertically opposite angles)
∠i
= 180° - 113° - 37°
= 30° (Angles sum of triangle)
(b)
∠k
= 180° - 30°
= 150° (Interior angles)
(c)
∠j
= 180° - 30° - 30° - 37°
= 97° (Angles sum of triangle)
Answer(s): (a) 30°; (b) 150°; (c) 97°