In the figure, DEF is parallel to JKL and the line JF cuts ∠EJL into half. Given that FJ and EK are straight lines, ∠DEJ = 48°, ∠JKH = 33° and ∠EHF = 115°, find
- ∠j
- ∠m
- ∠k
(a)
∠JHK = ∠EHF = 115° (Vertically opposite angles)
∠j
= 180° - 115° - 33°
= 32° (Angles sum of triangle)
(b)
∠m
= 180° - 32°
= 148° (Interior angles)
(c)
∠k
= 180° - 32° - 32° - 33°
= 99° (Angles sum of triangle)
Answer(s): (a) 32°; (b) 148°; (c) 99°